I make it a rule to never argue with a man who quotes Einstein. What you're saying, correct me if I'm wrong, is rate twists rates are not useful and are arbitrary based on the velocity of the bullet? The formula is D=RT, but that's forward velocity, not rotational velocity.
Source from bullet rotational speed website.
"Quick Version: MV X 720/Twist Rate = RPM
Example One: In a 1:12”³ twist barrel the bullet will make one complete revolution for every 12”³ (or 1 foot) it travels through the bore. This makes the RPM calculation very easy. With a velocity of 3000 feet per second (FPS), in a 1:12”³ twist barrel, the bullet will spin 3000 revolutions per SECOND (because it is traveling exactly one foot, and thereby making one complete revolution, in 1/3000 of a second). To convert to RPM, simply multiply by 60 since there are 60 seconds in a minute. Thus, at 3000 FPS, a bullet will be spinning at 3000 x 60, or 180,000 RPM, when it leaves the barrel.
Example Two: What about a faster twist rate, say a 1:8”³ twist? We know the bullet will be spinning faster than in Example One, but how much faster? Using the formula, this is simple to calculate. Assuming the same MV of 3000 FPS, the bullet makes 12/8 or 1.5 revolutions for each 12”³ or one foot it travels in the bore. Accordingly, the RPM is 3000 x (12/8) x 60, or 270,000 RPM."
Keep in mind, however, that bullets seldom rotate for a full minute before hitting the target or falling to the ground. So you have to figure out the time it's exposed, which will probably be 1/5 of a second of exposure.
Edited by Gene L on 12-17-15 03:59 PM. Reason for edit: added information