Wow, there are some smart people on this forum!Two other BP shooters I know have different opinions about RB rotation after it leaves the barrel. So, I am going to ask the experts here. A 50 cal, 48" barrel, with 1 revolution in 48" twist is fired using 60 grains of 2F.
When the RB leaves the muzzle it has already rotated 1 complete turn. Here is the question: Does the RB continue rotation of 1 turn every 4', or does it accelerate to a faster rotation?
If your just shootin and do not care why RBs do what they do, I agree. If one wants to know why a RB does what it does, then physics play a huge role in our shooting.It continues spinning at the rate it left the barrel (as if that really matters) .
SPOT ON!The moment it leaves the muzzle the ball depreciates, just like driving your new car off the lot...
Ok, let’s think about a ball in space. The ball is shot at 1600 fps relative the gun. It’s making a turn once every four feet.The RPM is entirely independent of the forward velocity once the ball leaves the muzzle. The RPM or angular velocity is established by the rate of twist and the velocity of the ball at the time of firing but has nothing to do with the distance it travels any time after leaving the barrel. If we have a barrel with a twist of 1 turn in 48" (constant twist and not gain twist rifling) and the barrel is 48" long It uses that length to reach the maximum velocity and after the ball exits the muzzle it begins to loose velocity and to drop due to air resistance and gravity. Those two forces however do not oppose the rotation of the ball and in turn slow it. The momentum of its spin (see: spin angular momentum) will continue to keep its angular velocity constant and that momentum must be overcome by something to change the rate of spin. If the RPM were to drop the projectile would loose stability. That would have a considerable effect on an elongated projection and I suspect a lesser effect on a round ball.
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You was doing good until you got to your "Wick and dirty math".Ok, let’s think about a ball in space. The ball is shot at 1600 fps relative the gun. It’s making a turn once every four feet.
We are in a vacuum. So one minute after it leave the gun the ball is still going 1600 fps. It will be 96000 feet from our muzzle.
It’s making one turn every four feet of that distance. It will have spin on its axis 24000 time in that minute. So it has an rpm of 24000.
Same gun differs powder charge.
1200 FPS. So now our ball travels 72000 feet in a min. In that minute it turns on its axis 18000 times its RPM is 18000.
The rate of twist remains the same one turn in four feet, but The time factor it takes to go four feet and compleat a revolution is longer. The ball has the same spin rate but lower Rotations per minute
Now we’re in space but we have a giant balloon filled with one atmosphere of pressure gas. So our ball is shot, it slows just like it dose on earth but doesn’t hit any ground.
It’s fired at 1600 fps, but by the time it reaches 300 feet from the muzzle it has slowed to 1100 fps, at two hundred yards 800 fps , and at three hundred yard 350 fps.
Wick and dirty math here since the deceleration related to air pressure isn’t constant but here goes
At the muzzle it’s 1600 fps 2400 rpm, at a hundred yards it’s 1100 fps 16500 rpm. Average speed is 1350 fps average RPM is 20250.
It will have turned on its axis seventy five time in that first hundred yards, and 75 in the next hundred yards, and seventy five in the third hundred yards. But the time it takes to go that hundred yards is longer and longer. At 350 fps it’s still turning on its axis one turn ever four feet, buts it’s taking longer and longer to go four feet. It’s RPM now is 5250.
You have to also take in to consideration the sides of the ball. Though it is a sphere, as it spins, the presence of the air is going to create friction against that spin, as all of the sphere is not encompassed by vacuum. Now it will take some fancy mathematics to show this drag, as it is a sphere and not a flat sided object, so there will be a graduated effect, but however slight that frictional drag may be, it is there and it will act in slowing the rotation.You was doing good until you got to your "Wick and dirty math".
I don't disagree with the idea that the linear velocity of the ball slowed down but the speed the ball spins would only change I'd guess maybe 50 or 100 RPM due to the wind causing circumferential drag on the forward face of the ball. (The back face of the ball is in a near vacuum because the air can't fill that area fast enough to make contact with the ball.)
In other words, the RPM of the ball does not change just because the velocity of the ball changes.
hawkeye2 got it completely right. Whatever velocity the ball drops to, spin rate remains almost constant. There is such a thing as "spin decay rate", but it's extremely small.The RPM is entirely independent of the forward velocity once the ball leaves the muzzle.
Not needed plus if you try to push it too hard, the ball strips and no longer follows the rifling. They do have guns with faster twist and they still shoot well with limitations. I have one with 1/20 twist.So if the ball can be stable at 1/30 turn rate, why don’t we build our guns with 1/30 twist?